That’s how I know I did this problem correctly. My y quantity I hope is equal to 2 times my x quantity take away 3. I also need to check it into the second equation. Good so I’m half way there, I think it's right.
SUBSTITUTION EQUATION SYSTEMS PLUS
So here comes my check, first I’m going to check it in the first equation, is it true that my y quantity is equal to 3 times my x quantity plus 1? Let’s see -11 equals -12 plus 1, yap that’s true.
In order to check my work, I’m going to go back and plug in -4 for x and -11 to y into both original equations and make sure I get equalities.
SUBSTITUTION EQUATION SYSTEMS HOW TO
As a warm-up or helpful review, students can complete Solving Systems of Linear Equation: Substitution, which walks through an example of how to solve systems of equations using the substitution method.
I’m pretty sure that’s my answer, I’m pretty sure that’s the point where these lines cross even though I didn’t graph them. This one-page practice worksheet offers 12 unique systems of linear equations to help students get comfortable using the substitution method. Y is equal to 3 times my x quantity plus 1, so y is equal to -11 oops, that’s a +1 right there, plus 1 okay. I could also use the second one and I’ll still get the same answer for y. I’m just going to choose to use the first equation. In order to find y, I’m going to take x equals -4, and substitute it into either original equation, that way I’ll get my y value, and I’ll go back and check in a second. I’m going to put a box around this like I would have with my whole answer keeping in mind I still need to find what that y value is. Keep in mind that’s only going to be half of my answer. Now I need to get x all by itself by subtracting 1 from both sides, x is equal to -4. Here we go if I want to find x, I’m going to subtract 2 Xs from both sides, so now I have x plus 1 equals -3. I’m going to find x, and then go back and find my y value. Now this is a straight forward solving problem. That guy is equal to y and that guy is also equal to y, so I’m just substituting those two equations so they look like one equation with one variable. Since I know y is equal to the expression 3x plus 1, and y is also equal to the expression 2x minus 3, it makes sense mathematically to write 3x plus 1 equals 2x minus 3. The salary options would be equal for 600 training sessions.This problem using substitution is going to be not too difficult because I have 2 equations that are both already solved for y. Substitute 25,000 + 15 n for s in the second equation.Īre 600 training sessions a year reasonable? We are looking for the number of training sessions How many training sessions would make the salary options equal? Answer Step 1. Option B would pay her $10,000 + $40 for each training session. Option A would pay her $25,000 plus $15 for each training session. Heather has been offered two options for her salary as a trainer at the gym. Times the measure of the other small angle. Of a right triangle is ten more than three Step 2 : Then substitute that expression for y in the other. We are looking for the measures of the angles. Systems of Linear equations: Step 1 : First, solve one linear equation for y in terms of x. The measure of one of the small angles of a right triangle is ten more than three times the measure of the other small angle.
0 kommentar(er)
